Collins, p.107
[cid:image001.jpg@01CC88F0.11386960] Note: ρfresh water = 1,000kg/m3; g = 10N/kg Q5: Pressure difference = height x density x strength of gravitational field P = hxpxg150 = h x 1000 x 10
h = 15m if he was in seawater he would be slightly less then 15m under sea level Q6: Pressure difference = height x density x strength of gravitational field P = hxpxg
increase in pressure = 24.4 kPa the total pressure = 189.4 kPa
No comments:
Post a Comment